5k^2+k-1=29

Solution for 5k^2+k-1=29 equation:

5k^2+k-1=29

We move all terms to the left:

5k^2+k-1-(29)=0

We add all the numbers together, and all the variables

5k^2+k-30=0

a = 5; b = 1; c = -30;
Δ = b2-4ac
Δ = 12-4·5·(-30)
Δ = 601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{601}}{2*5}=\frac{-1-\sqrt{601}}{10}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{601}}{2*5}=\frac{-1+\sqrt{601}}{10}
$